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**General Instructions :**

1. You have **20 minutes** to complete the Test.

2. The test contains **35 questions – 35 Marks**.

3. There is only one correct answer to each question. Click on the most appropriate option to mark it as your answer.

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- Question 1 of 35
##### 1. Question

Quantitative Aptitude**Find the wrong number in the following series.**15836 , 7920, 1984, 256, 32, 36

CorrectThe correct answer is

**option****5**i.e.**36**Understanding Application The series follows the pattern / 2 + 2, / 4 + 4, / 8 + 8, / 16 + 16, / 32 + 32 15836 / 2 + 2 = 7920

7920 / 4 + 4 = 1984

1984 / 8 + 8 = 256

256 / 16 + 16 = 32

32 / 32 + 32 = 33

Hence, the term **36**is wrong.IncorrectThe correct answer is

**option****5**i.e.**36**Understanding Application The series follows the pattern / 2 + 2, / 4 + 4, / 8 + 8, / 16 + 16, / 32 + 32 15836 / 2 + 2 = 7920

7920 / 4 + 4 = 1984

1984 / 8 + 8 = 256

256 / 16 + 16 = 32

32 / 32 + 32 = 33

Hence, the term **36**is wrong.UnattemptedThe correct answer is

**option****5**i.e.**36**Understanding Application The series follows the pattern / 2 + 2, / 4 + 4, / 8 + 8, / 16 + 16, / 32 + 32 15836 / 2 + 2 = 7920

7920 / 4 + 4 = 1984

1984 / 8 + 8 = 256

256 / 16 + 16 = 32

32 / 32 + 32 = 33

Hence, the term **36**is wrong. - Question 2 of 35
##### 2. Question

Quantitative Aptitude**Find the wrong number in the following series.**1, – 3 , – 4, 1, 18, 60

CorrectThe correct answer is

**option****1**i.e.**60**The series follows the pattern

= 1, – 3 , – 4, 1, 18, 59Difference between terms

= – 4, -1, 5, 17, 41Difference between terms

= 3, 6, 12, 24Hence, the wrong term is 60

IncorrectThe correct answer is

**option****1**i.e.**60**The series follows the pattern

= 1, – 3 , – 4, 1, 18, 59Difference between terms

= – 4, -1, 5, 17, 41Difference between terms

= 3, 6, 12, 24Hence, the wrong term is 60

UnattemptedThe correct answer is

**option****1**i.e.**60**The series follows the pattern

= 1, – 3 , – 4, 1, 18, 59Difference between terms

= – 4, -1, 5, 17, 41Difference between terms

= 3, 6, 12, 24Hence, the wrong term is 60

- Question 3 of 35
##### 3. Question

Quantitative Aptitude**Find the wrong number in the following series.**– 2, 0, – 3, 1, – 5, 2

CorrectThe correct answer is

**option****4**i.e.**– 5**Understanding Application The series follows the pattern + 2, – 3, + 4, – 5, + 6 – 2 + 2 = 0

0 – 3 = – 3

– 3 + 4 = 1

1 – 5 = – 4

– 4 + 6 = 2

Hence, the term **– 5**is wrong.IncorrectThe correct answer is

**option****4**i.e.**– 5**Understanding Application The series follows the pattern + 2, – 3, + 4, – 5, + 6 – 2 + 2 = 0

0 – 3 = – 3

– 3 + 4 = 1

1 – 5 = – 4

– 4 + 6 = 2

Hence, the term **– 5**is wrong.UnattemptedThe correct answer is

**option****4**i.e.**– 5**Understanding Application The series follows the pattern + 2, – 3, + 4, – 5, + 6 – 2 + 2 = 0

0 – 3 = – 3

– 3 + 4 = 1

1 – 5 = – 4

– 4 + 6 = 2

Hence, the term **– 5**is wrong. - Question 4 of 35
##### 4. Question

Quantitative Aptitude**Find the wrong number in the following series.**1, 13, 150, 1001, 5005, 15015

CorrectThe correct answer is

**option****1**i.e.**150**Understanding Application The series follows the pattern x 13, x 11, x 7, x 5, x 3 1 x 13 = 13

13 x 11 = 143

143 x 7 = 1001

1001 x 5 = 5005

5005 x 3 = 15015

Hence, the term **150**is wrong.IncorrectThe correct answer is

**option****1**i.e.**150**Understanding Application The series follows the pattern x 13, x 11, x 7, x 5, x 3 1 x 13 = 13

13 x 11 = 143

143 x 7 = 1001

1001 x 5 = 5005

5005 x 3 = 15015

Hence, the term **150**is wrong.UnattemptedThe correct answer is

**option****1**i.e.**150**Understanding Application The series follows the pattern x 13, x 11, x 7, x 5, x 3 1 x 13 = 13

13 x 11 = 143

143 x 7 = 1001

1001 x 5 = 5005

5005 x 3 = 15015

Hence, the term **150**is wrong. - Question 5 of 35
##### 5. Question

Quantitative Aptitude**Find the wrong number in the following series.**3, 4, 9, 30, 113, 566

CorrectThe correct answer is

**option****2**i.e.**30**Understanding Application The series follows the pattern : x 1 + 1, x 2 + 1, x 3 + 1, x 4 + 1, x 5 + 1 3 x 1 + 1 = 4

4 x 2 + 1 = 9

9 x 3 + 1 = 28

28 x 4 + 1 = 113

113 x 5 + 1 = 566

Hence, the term **30**is wrong.IncorrectThe correct answer is

**option****2**i.e.**30**Understanding Application The series follows the pattern : x 1 + 1, x 2 + 1, x 3 + 1, x 4 + 1, x 5 + 1 3 x 1 + 1 = 4

4 x 2 + 1 = 9

9 x 3 + 1 = 28

28 x 4 + 1 = 113

113 x 5 + 1 = 566

Hence, the term **30**is wrong.UnattemptedThe correct answer is

**option****2**i.e.**30**Understanding Application The series follows the pattern : x 1 + 1, x 2 + 1, x 3 + 1, x 4 + 1, x 5 + 1 3 x 1 + 1 = 4

4 x 2 + 1 = 9

9 x 3 + 1 = 28

28 x 4 + 1 = 113

113 x 5 + 1 = 566

Hence, the term **30**is wrong. - Question 6 of 35
##### 6. Question

Quantitative Aptitude**Direction:**A company manufactures Mouse and Keyboard. The line graph below shows the profit (In Rs.) earned by the company on the sale of Mouse and Keyboard in 5 different months. Study the graph carefully and answer the questions that follow. All the values in the graph are in crores.**What is the ratio of number of months in which Profit earned on the sale of Mouse is more than Keyboard and the number of months in which Profit earned on the sale of Mouse is less than Keyboard?**CorrectThe correct answer is Option 2 i.e. 4 : 1

Months in which Profit earned on the sale of Mouse is more than Keyboard are January, March, April and May i.e. 4 months.

And

Month in which Profit earned on the sale of Mouse is less than Keyboard is February i.e. 1 months.

Hence,

Required ratio = 4 : 1

IncorrectThe correct answer is Option 2 i.e. 4 : 1

Months in which Profit earned on the sale of Mouse is more than Keyboard are January, March, April and May i.e. 4 months.

And

Month in which Profit earned on the sale of Mouse is less than Keyboard is February i.e. 1 months.

Hence,

Required ratio = 4 : 1

UnattemptedThe correct answer is Option 2 i.e. 4 : 1

Months in which Profit earned on the sale of Mouse is more than Keyboard are January, March, April and May i.e. 4 months.

And

Month in which Profit earned on the sale of Mouse is less than Keyboard is February i.e. 1 months.

Hence,

Required ratio = 4 : 1

- Question 7 of 35
##### 7. Question

Quantitative Aptitude**Direction:**A company manufactures Mouse and Keyboard. The line graph below shows the profit (In Rs.) earned by the company on the sale of Mouse and Keyboard in 5 different months. Study the graph carefully and answer the questions that follow. All the values in the graph are in crores.**What is the difference between the average profit earned on the sale of Mouse in 5 months and average profit earned on the sale of Keyboard in 5 months?**CorrectThe correct answer is Option 1 i.e. 1.1 crores

From the line graph:

Average profit earned on the sale of Mouse in 5 months

= [5 + 3 + 5 + 6 + 3]/5

= 22/5 = 4.4 crores

And

Average profit earned on the sale of Keyboard in 5 months

= [4 + 3.5 + 4.5 + 2 + 2.5]/5

= 16.5/5 = 3.3 crores

Hence,

Required difference = 4.4 – 3.3 = 1.1 crores

IncorrectThe correct answer is Option 1 i.e. 1.1 crores

From the line graph:

Average profit earned on the sale of Mouse in 5 months

= [5 + 3 + 5 + 6 + 3]/5

= 22/5 = 4.4 crores

And

Average profit earned on the sale of Keyboard in 5 months

= [4 + 3.5 + 4.5 + 2 + 2.5]/5

= 16.5/5 = 3.3 crores

Hence,

Required difference = 4.4 – 3.3 = 1.1 crores

UnattemptedThe correct answer is Option 1 i.e. 1.1 crores

From the line graph:

Average profit earned on the sale of Mouse in 5 months

= [5 + 3 + 5 + 6 + 3]/5

= 22/5 = 4.4 crores

And

Average profit earned on the sale of Keyboard in 5 months

= [4 + 3.5 + 4.5 + 2 + 2.5]/5

= 16.5/5 = 3.3 crores

Hence,

Required difference = 4.4 – 3.3 = 1.1 crores

- Question 8 of 35
##### 8. Question

Quantitative Aptitude**Direction:**A company manufactures Mouse and Keyboard. The line graph below shows the profit (In Rs.) earned by the company on the sale of Mouse and Keyboard in 5 different months. Study the graph carefully and answer the questions that follow. All the values in the graph are in crores.**Total profit on the sale of Keyboards in March and May months together is percentage of total profit on the sale of Mouse in January and February months together?**CorrectThe correct answer is Option 5 i.e. 87.5%

From the line graph:

Total profit on the sale of Keyboards in March and May months together

= 4.5 + 2.5 = 7 crores

And

Total profit on the sale of Mouse in January and February months together

= 5 + 3 = 8 crores

Hence,

Required percentage = 7/8 × 100 = 87.5%

IncorrectThe correct answer is Option 5 i.e. 87.5%

From the line graph:

Total profit on the sale of Keyboards in March and May months together

= 4.5 + 2.5 = 7 crores

And

Total profit on the sale of Mouse in January and February months together

= 5 + 3 = 8 crores

Hence,

Required percentage = 7/8 × 100 = 87.5%

UnattemptedThe correct answer is Option 5 i.e. 87.5%

From the line graph:

Total profit on the sale of Keyboards in March and May months together

= 4.5 + 2.5 = 7 crores

And

Total profit on the sale of Mouse in January and February months together

= 5 + 3 = 8 crores

Hence,

Required percentage = 7/8 × 100 = 87.5%

- Question 9 of 35
##### 9. Question

Quantitative Aptitude**Direction:**A company manufactures Mouse and Keyboard. The line graph below shows the profit (In Rs.) earned by the company on the sale of Mouse and Keyboard in 5 different months. Study the graph carefully and answer the questions that follow. All the values in the graph are in crores.**Determine the ratio of the average profit earned on the sale of mouse in January and February and average profit earned on the sale of Keyboards in April and February.**CorrectThe correct answer is Option 3 i.e. 16 : 11

From the line graph:

Average profit earned on the sale of mouse in January and February

= [5 + 3]/2 = 4 crores

And

Average profit earned on the sale of Keyboards in April and February

= [3.5 + 2]/2 = 2.75 crores

Hence,

Required ratio = 4 : 2.75 = 16 : 11

IncorrectThe correct answer is Option 3 i.e. 16 : 11

From the line graph:

Average profit earned on the sale of mouse in January and February

= [5 + 3]/2 = 4 crores

And

Average profit earned on the sale of Keyboards in April and February

= [3.5 + 2]/2 = 2.75 crores

Hence,

Required ratio = 4 : 2.75 = 16 : 11

UnattemptedThe correct answer is Option 3 i.e. 16 : 11

From the line graph:

Average profit earned on the sale of mouse in January and February

= [5 + 3]/2 = 4 crores

And

Average profit earned on the sale of Keyboards in April and February

= [3.5 + 2]/2 = 2.75 crores

Hence,

Required ratio = 4 : 2.75 = 16 : 11

- Question 10 of 35
##### 10. Question

Quantitative Aptitude**Direction:**A company manufactures Mouse and Keyboard. The line graph below shows the profit (In Rs.) earned by the company on the sale of Mouse and Keyboard in 5 different months. Study the graph carefully and answer the questions that follow. All the values in the graph are in crores.**Total profit in the month in which maximum profit (sum of profits on the sale of mouse and keyboards) is earned by the company is what percentage of the total profit in the month in which minimum profit (sum of profits on the sale of mouse and keyboards) is earned by the company?**CorrectThe correct answer is Option 2 i.e. 172.72%

From the Line graph:

The company earned maximum total profit in the month of March i.e. 5 + 4.5 = 9.5 crores

And

The company earned minimum total profit in the month of May i.e. 3 + 2.5 = 5.5 crores

Hence,

Required ratio = 9.5/5.5 × 100 = 172.72%

IncorrectThe correct answer is Option 2 i.e. 172.72%

From the Line graph:

The company earned maximum total profit in the month of March i.e. 5 + 4.5 = 9.5 crores

And

The company earned minimum total profit in the month of May i.e. 3 + 2.5 = 5.5 crores

Hence,

Required ratio = 9.5/5.5 × 100 = 172.72%

UnattemptedThe correct answer is Option 2 i.e. 172.72%

From the Line graph:

The company earned maximum total profit in the month of March i.e. 5 + 4.5 = 9.5 crores

And

The company earned minimum total profit in the month of May i.e. 3 + 2.5 = 5.5 crores

Hence,

Required ratio = 9.5/5.5 × 100 = 172.72%

- Question 11 of 35
##### 11. Question

Quantitative AptitudeThe table below shows the percentage of total shares with Investors, Employees and Public of 4 different companies A, B, C and D. Study the table carefully and answer the questions.**Direction:****Company****Total shares****Percentage of total shares with Investors****Percentage of total shares with Employees****Percentage of total shares with Public****A**100000 65% 20% 15% **B**50000 75% 15% 10% **C**300000 60% 10% 30% **D**500000 55% 25% 20% **Find the difference of total number of shares with Public in companies B and D together and total number of shares with Employees in companies A and C together.**CorrectThe correct answer is Option 3 i.e. 55000

From the table:

Total number of shares with Employees in companies A and C together

= 100000 × 0.2 + 300000 × 0.1 = 50000

And

Total number of shares with Public in companies B and D together

= 50000 × 0.1 + 500000 × 0.2 = 105000

Hence,

Required difference = 105000 – 50000 = 55000

IncorrectThe correct answer is Option 3 i.e. 55000

From the table:

Total number of shares with Employees in companies A and C together

= 100000 × 0.2 + 300000 × 0.1 = 50000

And

Total number of shares with Public in companies B and D together

= 50000 × 0.1 + 500000 × 0.2 = 105000

Hence,

Required difference = 105000 – 50000 = 55000

UnattemptedThe correct answer is Option 3 i.e. 55000

From the table:

Total number of shares with Employees in companies A and C together

= 100000 × 0.2 + 300000 × 0.1 = 50000

And

Total number of shares with Public in companies B and D together

= 50000 × 0.1 + 500000 × 0.2 = 105000

Hence,

Required difference = 105000 – 50000 = 55000

- Question 12 of 35
##### 12. Question

Quantitative AptitudeThe table below shows the percentage of total shares with Investors, Employees and Public of 4 different companies A, B, C and D. Study the table carefully and answer the questions.**Direction:****Company****Total shares****Percentage of total shares with Investors****Percentage of total shares with Employees****Percentage of total shares with Public****A**100000 65% 20% 15% **B**50000 75% 15% 10% **C**300000 60% 10% 30% **D**500000 55% 25% 20% **Total number of shares with Investors in companies A and D together is how much percentage more than the total number of shares with Public in companies A and B together?**CorrectThe correct answer is Option 4 i.e. 1600%

From the table:

Total number of shares with Investors in companies A and D together

= 100000 × 0.65 + 500000 × 0.55 = 340000

And

Total number of shares with Public in companies A and B together

= 100000 × 0.15 + 50000 × 0.1 = 20000

Hence,

Required percentage = [(340000 – 20000)/20000] × 100 = 1600%

IncorrectThe correct answer is Option 4 i.e. 1600%

From the table:

Total number of shares with Investors in companies A and D together

= 100000 × 0.65 + 500000 × 0.55 = 340000

And

Total number of shares with Public in companies A and B together

= 100000 × 0.15 + 50000 × 0.1 = 20000

Hence,

Required percentage = [(340000 – 20000)/20000] × 100 = 1600%

UnattemptedThe correct answer is Option 4 i.e. 1600%

From the table:

Total number of shares with Investors in companies A and D together

= 100000 × 0.65 + 500000 × 0.55 = 340000

And

Total number of shares with Public in companies A and B together

= 100000 × 0.15 + 50000 × 0.1 = 20000

Hence,

Required percentage = [(340000 – 20000)/20000] × 100 = 1600%

- Question 13 of 35
##### 13. Question

Quantitative AptitudeThe table below shows the percentage of total shares with Investors, Employees and Public of 4 different companies A, B, C and D. Study the table carefully and answer the questions.**Direction:****Company****Total shares****Percentage of total shares with Investors****Percentage of total shares with Employees****Percentage of total shares with Public****A**100000 65% 20% 15% **B**50000 75% 15% 10% **C**300000 60% 10% 30% **D**500000 55% 25% 20% **If the company D increases the number of shares offered to its employees to 160000 reducing the shares offered to Public then find the percentage reduction the number of shares offered to Public by company D.**CorrectThe correct answer is Option 2 i.e. 35%

From the table:

Number of shares offered to its employees by company D = 500000 × 0.25 = 125000

And it is increased to 160000.

Hence,

Decrease in number of shares offered to Public by company D = 160000 – 125000 = 35000

And

Number of shares offered to Public by company D = 500000 × 0.1 = 100000

Hence,

Percentage reduction = 35000/100000 × 100 = 35%

IncorrectThe correct answer is Option 2 i.e. 35%

From the table:

Number of shares offered to its employees by company D = 500000 × 0.25 = 125000

And it is increased to 160000.

Hence,

Decrease in number of shares offered to Public by company D = 160000 – 125000 = 35000

And

Number of shares offered to Public by company D = 500000 × 0.1 = 100000

Hence,

Percentage reduction = 35000/100000 × 100 = 35%

UnattemptedThe correct answer is Option 2 i.e. 35%

From the table:

Number of shares offered to its employees by company D = 500000 × 0.25 = 125000

And it is increased to 160000.

Hence,

Decrease in number of shares offered to Public by company D = 160000 – 125000 = 35000

And

Number of shares offered to Public by company D = 500000 × 0.1 = 100000

Hence,

Percentage reduction = 35000/100000 × 100 = 35%

- Question 14 of 35
##### 14. Question

Quantitative AptitudeThe table below shows the percentage of total shares with Investors, Employees and Public of 4 different companies A, B, C and D. Study the table carefully and answer the questions.**Direction:****Company****Total shares****Percentage of total shares with Investors****Percentage of total shares with Employees****Percentage of total shares with Public****A**100000 65% 20% 15% **B**50000 75% 15% 10% **C**300000 60% 10% 30% **D**500000 55% 25% 20% **What is the average of number of shares with Investors in 4 companies?**CorrectThe correct answer is Option 1 i.e. 139375

From the table:

Average of number of shares with Investors in 4 companies

= [100000 × 0.65 + 50000 × 0.75 + 300000 × 0.6 + 500000 × 0.55]/4

= [65000 + 37500 + 180000 + 275000/4

= 557500/4

= 139375

IncorrectThe correct answer is Option 1 i.e. 139375

From the table:

Average of number of shares with Investors in 4 companies

= [100000 × 0.65 + 50000 × 0.75 + 300000 × 0.6 + 500000 × 0.55]/4

= [65000 + 37500 + 180000 + 275000/4

= 557500/4

= 139375

UnattemptedThe correct answer is Option 1 i.e. 139375

From the table:

Average of number of shares with Investors in 4 companies

= [100000 × 0.65 + 50000 × 0.75 + 300000 × 0.6 + 500000 × 0.55]/4

= [65000 + 37500 + 180000 + 275000/4

= 557500/4

= 139375

- Question 15 of 35
##### 15. Question

Quantitative AptitudeThe table below shows the percentage of total shares with Investors, Employees and Public of 4 different companies A, B, C and D. Study the table carefully and answer the questions.**Direction:****Company****Total shares****Percentage of total shares with Investors****Percentage of total shares with Employees****Percentage of total shares with Public****A**100000 65% 20% 15% **B**50000 75% 15% 10% **C**300000 60% 10% 30% **D**500000 55% 25% 20% **Find the ratio of total number of shares with Public in companies C and D together and total number of shares with Employees in companies A and B together.**CorrectThe correct answer is Option 4 i.e. 76 : 11

From the table:

Total number of shares with Public in companies C and D together

= 300000 × 0.3 + 500000 × 0.2 = 190000

And

Total number of shares with Employees in companies A and B together

= 100000 × 0.2 + 50000 × 0.15 = 27500

Hence,

Required ratio = 190000 : 27500 = 76 : 11

IncorrectThe correct answer is Option 4 i.e. 76 : 11

From the table:

Total number of shares with Public in companies C and D together

= 300000 × 0.3 + 500000 × 0.2 = 190000

And

Total number of shares with Employees in companies A and B together

= 100000 × 0.2 + 50000 × 0.15 = 27500

Hence,

Required ratio = 190000 : 27500 = 76 : 11

UnattemptedThe correct answer is Option 4 i.e. 76 : 11

From the table:

Total number of shares with Public in companies C and D together

= 300000 × 0.3 + 500000 × 0.2 = 190000

And

Total number of shares with Employees in companies A and B together

= 100000 × 0.2 + 50000 × 0.15 = 27500

Hence,

Required ratio = 190000 : 27500 = 76 : 11

- Question 16 of 35
##### 16. Question

Quantitative Aptitude**In the following question, two statements numbered I and II are given. Solve both the equations and mark your answer accordingly.**I. 3x

^{2}– 10x + 8 = 0II. 4y

^{2}+ 5y – 6 = 0CorrectThe correct answer is

**Option 1**i.e.**x > y**Equation I Equation II 3x ^{2}– 10x + 8 = 04y ^{2}+ 5y – 6 = 03x ^{2}– 6x – 4x + 8 = 04y ^{2}+ 8y – 3y – 6 = 03x(x – 2) – 4(x – 2) = 0 4y(y + 2) – 3(y + 2) = 0 (x – 2) (3x – 4) = 0 (y + 2) (4y -3) x = 2, 4/3 y = -2, 3/4 Now we can analyze

Value of x Value of y Result 2 -2 x > y 2 3/4 x > y 4/3 -2 x > y 4/3 3/4 x > y Hence x > y

IncorrectThe correct answer is

**Option 1**i.e.**x > y**Equation I Equation II 3x ^{2}– 10x + 8 = 04y ^{2}+ 5y – 6 = 03x ^{2}– 6x – 4x + 8 = 04y ^{2}+ 8y – 3y – 6 = 03x(x – 2) – 4(x – 2) = 0 4y(y + 2) – 3(y + 2) = 0 (x – 2) (3x – 4) = 0 (y + 2) (4y -3) x = 2, 4/3 y = -2, 3/4 Now we can analyze

Value of x Value of y Result 2 -2 x > y 2 3/4 x > y 4/3 -2 x > y 4/3 3/4 x > y Hence x > y

UnattemptedThe correct answer is

**Option 1**i.e.**x > y**Equation I Equation II 3x ^{2}– 10x + 8 = 04y ^{2}+ 5y – 6 = 03x ^{2}– 6x – 4x + 8 = 04y ^{2}+ 8y – 3y – 6 = 03x(x – 2) – 4(x – 2) = 0 4y(y + 2) – 3(y + 2) = 0 (x – 2) (3x – 4) = 0 (y + 2) (4y -3) x = 2, 4/3 y = -2, 3/4 Now we can analyze

Value of x Value of y Result 2 -2 x > y 2 3/4 x > y 4/3 -2 x > y 4/3 3/4 x > y Hence x > y

- Question 17 of 35
##### 17. Question

Quantitative Aptitude**In the following question, two statements numbered I and II are given. Solve both the equations and mark your answer accordingly.**I. 2x

^{2}+ x – 1 = 0II. 2y

^{2}– 3y + 1 = 0CorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II 2x ^{2}+ x – 1 = 02y ^{2}– 3y + 1 = 02x ^{2}+ 2x – x – 1 = 02y ^{2}– 2y – y + 1 = 02x(x + 1) – 1(x + 1) = 0 2y(y – 1) – (y – 1) = 0 (x + 1) (2x – 1) = 0 (y – 1) (2y – 1) = 0 x = -1, 1/2 y = 1, 1/2 Thus we can analyze

Value of x Value of y Result -1 1 x < y -1 1/2 x < y 1/2 1 x < y 1/2 1/2 x = y Hence x = y or relationship can’t be determined

IncorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II 2x ^{2}+ x – 1 = 02y ^{2}– 3y + 1 = 02x ^{2}+ 2x – x – 1 = 02y ^{2}– 2y – y + 1 = 02x(x + 1) – 1(x + 1) = 0 2y(y – 1) – (y – 1) = 0 (x + 1) (2x – 1) = 0 (y – 1) (2y – 1) = 0 x = -1, 1/2 y = 1, 1/2 Thus we can analyze

Value of x Value of y Result -1 1 x < y -1 1/2 x < y 1/2 1 x < y 1/2 1/2 x = y Hence x = y or relationship can’t be determined

UnattemptedThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II 2x ^{2}+ x – 1 = 02y ^{2}– 3y + 1 = 02x ^{2}+ 2x – x – 1 = 02y ^{2}– 2y – y + 1 = 02x(x + 1) – 1(x + 1) = 0 2y(y – 1) – (y – 1) = 0 (x + 1) (2x – 1) = 0 (y – 1) (2y – 1) = 0 x = -1, 1/2 y = 1, 1/2 Thus we can analyze

Value of x Value of y Result -1 1 x < y -1 1/2 x < y 1/2 1 x < y 1/2 1/2 x = y Hence x = y or relationship can’t be determined

- Question 18 of 35
##### 18. Question

Quantitative Aptitude**In the following question, two statements numbered I and II are given. Solve both the equations and mark your answer accordingly.**I. x

^{2}+ 15x + 50 = 0II. y

^{2}– 14y + 24 = 0CorrectThe correct answer is

**Option 2**i.e.**x < y**Equation I Equation II x ^{2}+ 15x + 50 = 0y ^{2}– 14y + 24 = 0x ^{2}+ 10x + 5x + 50 = 0y ^{2}– 12y – 2y + 24 = 0x(x + 10) + 5(x + 10) = 0 y(y – 12) – 2(y – 12) = 0 (x + 10) ( x + 5) = 0 (y – 12) (y – 2) = 0 x = -10 , -5 y = 12, 2 Thus we can analyze

Value of x Value of y Result -10 12 x < y -10 2 x < y -5 12 x < y -5 2 x < y IncorrectThe correct answer is

**Option 2**i.e.**x < y**Equation I Equation II x ^{2}+ 15x + 50 = 0y ^{2}– 14y + 24 = 0x ^{2}+ 10x + 5x + 50 = 0y ^{2}– 12y – 2y + 24 = 0x(x + 10) + 5(x + 10) = 0 y(y – 12) – 2(y – 12) = 0 (x + 10) ( x + 5) = 0 (y – 12) (y – 2) = 0 x = -10 , -5 y = 12, 2 Thus we can analyze

Value of x Value of y Result -10 12 x < y -10 2 x < y -5 12 x < y -5 2 x < y UnattemptedThe correct answer is

**Option 2**i.e.**x < y**Equation I Equation II x ^{2}+ 15x + 50 = 0y ^{2}– 14y + 24 = 0x ^{2}+ 10x + 5x + 50 = 0y ^{2}– 12y – 2y + 24 = 0x(x + 10) + 5(x + 10) = 0 y(y – 12) – 2(y – 12) = 0 (x + 10) ( x + 5) = 0 (y – 12) (y – 2) = 0 x = -10 , -5 y = 12, 2 Thus we can analyze

Value of x Value of y Result -10 12 x < y -10 2 x < y -5 12 x < y -5 2 x < y - Question 19 of 35
##### 19. Question

Quantitative AptitudeI. x

^{2}– 14x + 13 = 0II. y

^{2}– 17y + 30 = 0CorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 14x + 13 = 0y ^{2}– 17y + 30 = 0x ^{2}– 13x – x + 13 = 0y ^{2}– 15y – 2y + 30 = 0x(x – 13) – 1(x – 13) = 0 y(y – 15) – 2(y – 15) = 0 (x – 13) (x – 1) = 0 (y – 15) (y – 2) = 0 x = 1, 13 y = 15, 2 Thus we can analyze

Value of x Value of y Result 1 15 x < y 1 2 x < y 13 15 x < y 13 2 x > y Hence x = y or relationship can’t be determined

IncorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 14x + 13 = 0y ^{2}– 17y + 30 = 0x ^{2}– 13x – x + 13 = 0y ^{2}– 15y – 2y + 30 = 0x(x – 13) – 1(x – 13) = 0 y(y – 15) – 2(y – 15) = 0 (x – 13) (x – 1) = 0 (y – 15) (y – 2) = 0 x = 1, 13 y = 15, 2 Thus we can analyze

Value of x Value of y Result 1 15 x < y 1 2 x < y 13 15 x < y 13 2 x > y Hence x = y or relationship can’t be determined

UnattemptedThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 14x + 13 = 0y ^{2}– 17y + 30 = 0x ^{2}– 13x – x + 13 = 0y ^{2}– 15y – 2y + 30 = 0x(x – 13) – 1(x – 13) = 0 y(y – 15) – 2(y – 15) = 0 (x – 13) (x – 1) = 0 (y – 15) (y – 2) = 0 x = 1, 13 y = 15, 2 Thus we can analyze

Value of x Value of y Result 1 15 x < y 1 2 x < y 13 15 x < y 13 2 x > y Hence x = y or relationship can’t be determined

- Question 20 of 35
##### 20. Question

Quantitative AptitudeI. x

^{2}– 11x + 18 = 0II. y

^{2}+ 5y – 14 = 0CorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 11x + 18 = 0y ^{2}+ 5y – 14 = 0x ^{2}– 9x – 2x + 18 = 0y ^{2}+ 7y – 2y – 14 = 0x(x – 9) – 2(x – 9) = 0 y(y + 7) – 2(y – 7) = 0 (x – 9) (x – 2) = 0 (y – 7) (y – 2) = 0 x = 9, 2 y = 7, 2 Thus we can analyze

Value of x Value of y Result 9 7 x > y 9 2 x > y 2 7 x < y 2 2 x = y Hence x = y or relationship can’t be determined

IncorrectThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 11x + 18 = 0y ^{2}+ 5y – 14 = 0x ^{2}– 9x – 2x + 18 = 0y ^{2}+ 7y – 2y – 14 = 0x(x – 9) – 2(x – 9) = 0 y(y + 7) – 2(y – 7) = 0 (x – 9) (x – 2) = 0 (y – 7) (y – 2) = 0 x = 9, 2 y = 7, 2 Thus we can analyze

Value of x Value of y Result 9 7 x > y 9 2 x > y 2 7 x < y 2 2 x = y Hence x = y or relationship can’t be determined

UnattemptedThe correct answer is

**Option 5**i.e.**x = y or relationship can’t be determined**Equation I Equation II x ^{2}– 11x + 18 = 0y ^{2}+ 5y – 14 = 0x ^{2}– 9x – 2x + 18 = 0y ^{2}+ 7y – 2y – 14 = 0x(x – 9) – 2(x – 9) = 0 y(y + 7) – 2(y – 7) = 0 (x – 9) (x – 2) = 0 (y – 7) (y – 2) = 0 x = 9, 2 y = 7, 2 Thus we can analyze

Value of x Value of y Result 9 7 x > y 9 2 x > y 2 7 x < y 2 2 x = y Hence x = y or relationship can’t be determined

- Question 21 of 35
##### 21. Question

Quantitative AptitudeThree friends Rahul, Vishal and Abhishek start a business with an investment of 9550, 8550 and 7500 respectively. If the profit is 40960 at the end of the year, then find the average profit of Rahul and Vishal.

CorrectThe correct answer is

**Option 1**i.e.**14480**Understanding Application Tricks Profit = Investment × time Rahul Vishal Abhishek 9550 × 12 8550 × 12 7500 × 12 191 171 150 Now If 512 unit = 40960 So,

Profit of Rahul = 40960/512 × 191

= 80 × 191

= 15280

&

profit of Vishal = 40960/512 × 171

= 13680

Hence Average = (15280 + 13680)/2 = 28960/2

= 14480

IncorrectThe correct answer is

**Option 1**i.e.**14480**Understanding Application Tricks Profit = Investment × time Rahul Vishal Abhishek 9550 × 12 8550 × 12 7500 × 12 191 171 150 Now If 512 unit = 40960 So,

Profit of Rahul = 40960/512 × 191

= 80 × 191

= 15280

&

profit of Vishal = 40960/512 × 171

= 13680

Hence Average = (15280 + 13680)/2 = 28960/2

= 14480

UnattemptedThe correct answer is

**Option 1**i.e.**14480**Understanding Application Tricks Profit = Investment × time Rahul Vishal Abhishek 9550 × 12 8550 × 12 7500 × 12 191 171 150 Now If 512 unit = 40960 So,

Profit of Rahul = 40960/512 × 191

= 80 × 191

= 15280

&

profit of Vishal = 40960/512 × 171

= 13680

Hence Average = (15280 + 13680)/2 = 28960/2

= 14480

- Question 22 of 35
##### 22. Question

Quantitative AptitudeThe age of Rahul is 160% of the age of Vishal. Find the age of Vishal is what percent of the age of Rahul?

CorrectThe correct answer is

**Option 2**i.e.**62.5%**Understanding Application Tricks Rahul Vishal 8 5 Now If 8 = 100% then

5 = 100/8 × 5

= 62.5%

Hence Vishal age is 62.5% of the age of Rahul IncorrectThe correct answer is

**Option 2**i.e.**62.5%**Understanding Application Tricks Rahul Vishal 8 5 Now If 8 = 100% then

5 = 100/8 × 5

= 62.5%

Hence Vishal age is 62.5% of the age of Rahul UnattemptedThe correct answer is

**Option 2**i.e.**62.5%**Understanding Application Tricks Rahul Vishal 8 5 Now If 8 = 100% then

5 = 100/8 × 5

= 62.5%

Hence Vishal age is 62.5% of the age of Rahul - Question 23 of 35
##### 23. Question

Quantitative AptitudeRam goes to a shop by running to buy a school bag with a speed of 8 km/ hour and after purchasing bag he returns on the same way with a speed of 6 km/hour. Find the average speed of the Ram.

CorrectThe correct answer is

**Option 3**i.e.**6.85 km/hour**Understanding Application Tricks Average speed = (2 × 1st speed × 2nd speed)/1st speed + 2nd speed = 2 × 8 ×6/(8 + 6)

= 96/14

= 6.85

Hence 6.85 km/hour IncorrectThe correct answer is

**Option 3**i.e.**6.85 km/hour**Understanding Application Tricks Average speed = (2 × 1st speed × 2nd speed)/1st speed + 2nd speed = 2 × 8 ×6/(8 + 6)

= 96/14

= 6.85

Hence 6.85 km/hour UnattemptedThe correct answer is

**Option 3**i.e.**6.85 km/hour**Understanding Application Tricks Average speed = (2 × 1st speed × 2nd speed)/1st speed + 2nd speed = 2 × 8 ×6/(8 + 6)

= 96/14

= 6.85

Hence 6.85 km/hour - Question 24 of 35
##### 24. Question

Quantitative AptitudeA shopkeeper sells his article at a discount of 10% after giving discount shopkeepers gets profit of a 15%. If the selling price of the article is Rs.2645 then find the cost price of the article for the shopkeeper.

CorrectThe correct answer is

**option 4**i.e.**Rs.2300**Understanding Application Tricks If 115% = 2645 then

100% = 2645/115 × 100

= 2300

Hence CP = 2300 IncorrectThe correct answer is

**option 4**i.e.**Rs.2300**Understanding Application Tricks If 115% = 2645 then

100% = 2645/115 × 100

= 2300

Hence CP = 2300 UnattemptedThe correct answer is

**option 4**i.e.**Rs.2300**Understanding Application Tricks If 115% = 2645 then

100% = 2645/115 × 100

= 2300

Hence CP = 2300 - Question 25 of 35
##### 25. Question

Quantitative AptitudeIf two cards are come out from the well-shuffle of 52 cards. Find what is the probability of one card is red from these two cards?

CorrectThe correct answer is

**Option 5**i.e.**13/34**Understanding Application Tricks n(S) = ^{52}C_{2}= (52 × 51)/2

= 26 × 51

= 1326

&

n(E) =

^{13}C_{1}= 13 × 19

= 247

Now =p(E) = 247/1326 = 13/34

IncorrectThe correct answer is

**Option 5**i.e.**13/34**Understanding Application Tricks n(S) = ^{52}C_{2}= (52 × 51)/2

= 26 × 51

= 1326

&

n(E) =

^{13}C_{1}= 13 × 19

= 247

Now =p(E) = 247/1326 = 13/34

UnattemptedThe correct answer is

**Option 5**i.e.**13/34**Understanding Application Tricks n(S) = ^{52}C_{2}= (52 × 51)/2

= 26 × 51

= 1326

&

n(E) =

^{13}C_{1}= 13 × 19

= 247

Now =p(E) = 247/1326 = 13/34

- Question 26 of 35
##### 26. Question

Quantitative Aptitude**What will come in the place of question mark (?) in the following questions?**?

^{2 }+ 34.68 % of 1495.89 + 279 = 3420.679CorrectThe correct answer is

**Option 2**i.e.**52.**Application ? ^{2}+ 34.68% of 1495.89 + 279 = 3420.679?

^{2 }= 3421 – (35% of 1496 + 279)?

^{2}= 3421 – (30% of 1496 + 5% of 1496 + 279)?

^{2 }= 3421 – (448.8 + 74.8 + 279)?

^{2}= 3421 – (802.6)?

^{2 }= 2618 = ?^{2 }= (52)^{2}^{}? = 52Hence the correct answer is option 2

IncorrectThe correct answer is

**Option 2**i.e.**52.**Application ? ^{2}+ 34.68% of 1495.89 + 279 = 3420.679?

^{2 }= 3421 – (35% of 1496 + 279)?

^{2}= 3421 – (30% of 1496 + 5% of 1496 + 279)?

^{2 }= 3421 – (448.8 + 74.8 + 279)?

^{2}= 3421 – (802.6)?

^{2 }= 2618 = ?^{2 }= (52)^{2}^{}? = 52Hence the correct answer is option 2

UnattemptedThe correct answer is

**Option 2**i.e.**52.**Application ? ^{2}+ 34.68% of 1495.89 + 279 = 3420.679?

^{2 }= 3421 – (35% of 1496 + 279)?

^{2}= 3421 – (30% of 1496 + 5% of 1496 + 279)?

^{2 }= 3421 – (448.8 + 74.8 + 279)?

^{2}= 3421 – (802.6)?

^{2 }= 2618 = ?^{2 }= (52)^{2}^{}? = 52Hence the correct answer is option 2

- Question 27 of 35
##### 27. Question

Quantitative Aptitude**what approximate value will come in the place of question mark(?) in the following questions?**(24/9)

^{2}× (399/39) / (41/899) = ?CorrectThe correct answer is

**Option****1**i.e.**1600.**Application (24/9) ^{2}× (399/39)/(41/899) = ?? = (24/8)

^{2}× (400/40)/(40/900)? = (8/3)

^{2}× (400/40)/(900/40)? = (64/9) × (400/40)/(900/40)

? = 1600 (approx)

Hence the correct option is answer 1.

IncorrectThe correct answer is

**Option****1**i.e.**1600.**Application (24/9) ^{2}× (399/39)/(41/899) = ?? = (24/8)

^{2}× (400/40)/(40/900)? = (8/3)

^{2}× (400/40)/(900/40)? = (64/9) × (400/40)/(900/40)

? = 1600 (approx)

Hence the correct option is answer 1.

UnattemptedThe correct answer is

**Option****1**i.e.**1600.**Application (24/9) ^{2}× (399/39)/(41/899) = ?? = (24/8)

^{2}× (400/40)/(40/900)? = (8/3)

^{2}× (400/40)/(900/40)? = (64/9) × (400/40)/(900/40)

? = 1600 (approx)

Hence the correct option is answer 1.

- Question 28 of 35
##### 28. Question

Quantitative Aptitude**what approximate value will come in the place of question mark(?) in the following questions?**(3 / 10) of 111 = ? / (1.8 × 0.499)

CorrectThe correct answer is

**O****ption 4 i.e. 30**Application (3/10) of 111 = ?/(1.8 × 0.499) (3/10) × 110 = ?/(2 × 0.5)

3 × 11 = ?/1

? = 33

? = 30(approx).

IncorrectThe correct answer is

**O****ption 4 i.e. 30**Application (3/10) of 111 = ?/(1.8 × 0.499) (3/10) × 110 = ?/(2 × 0.5)

3 × 11 = ?/1

? = 33

? = 30(approx).

UnattemptedThe correct answer is

**O****ption 4 i.e. 30**Application (3/10) of 111 = ?/(1.8 × 0.499) (3/10) × 110 = ?/(2 × 0.5)

3 × 11 = ?/1

? = 33

? = 30(approx).

- Question 29 of 35
##### 29. Question

Quantitative Aptitude**what approximate value will come in the place of question mark(?) in the following questions?**(2/3)

^{3}× 81 + (1/5)^{3}= ?CorrectThe correct answer is

**Option 1 i.e. 3001/125**Application (2/3) ^{3}× 81 + (1/5)^{3}= ?(8/27) × 81 + (1/125) = ?

24 + (1/125) = ?

? = 3001/125.

IncorrectThe correct answer is

**Option 1 i.e. 3001/125**Application (2/3) ^{3}× 81 + (1/5)^{3}= ?(8/27) × 81 + (1/125) = ?

24 + (1/125) = ?

? = 3001/125.

UnattemptedThe correct answer is

**Option 1 i.e. 3001/125**Application (2/3) ^{3}× 81 + (1/5)^{3}= ?(8/27) × 81 + (1/125) = ?

24 + (1/125) = ?

? = 3001/125.

- Question 30 of 35
##### 30. Question

Quantitative Aptitude**what approximate value will come in the place of question mark(?) in the following questions?**3739 + 164 of 27 = ?

CorrectThe correct answer is

**Option 3 i.e. 8200**Application 3739 + 164 of 27 = ? ? = 3739 + 164 × 27

? = 3739 + 4428

? = 8200.

Hence the correct answer is option 3

IncorrectThe correct answer is

**Option 3 i.e. 8200**Application 3739 + 164 of 27 = ? ? = 3739 + 164 × 27

? = 3739 + 4428

? = 8200.

Hence the correct answer is option 3

UnattemptedThe correct answer is

**Option 3 i.e. 8200**Application 3739 + 164 of 27 = ? ? = 3739 + 164 × 27

? = 3739 + 4428

? = 8200.

Hence the correct answer is option 3

- Question 31 of 35
##### 31. Question

Quantitative Aptitude**what approximate value will come in the place of question mark(?) in the following questions?**(127.998 × 10.012 × 6400

^{1/2}) ÷ 100 = (?)^{2}CorrectThe correct answer is

**O****ption 2 i.e. 32**Application (127.998 × 10.012 × 6400 ^{1/2}) ÷ 100 = (?)^{2}{(128 × 10) × 6400

^{1/2}}/100 = ?^{2}(128 × 10 × 80)/100 = ?

^{2}?

^{2 }=128 × 8? = 1024

^{1/2}? = 32.

Hence the correct option is 2.

IncorrectThe correct answer is

**O****ption 2 i.e. 32**Application (127.998 × 10.012 × 6400 ^{1/2}) ÷ 100 = (?)^{2}{(128 × 10) × 6400

^{1/2}}/100 = ?^{2}(128 × 10 × 80)/100 = ?

^{2}?

^{2 }=128 × 8? = 1024

^{1/2}? = 32.

Hence the correct option is 2.

UnattemptedThe correct answer is

**O****ption 2 i.e. 32**Application (127.998 × 10.012 × 6400 ^{1/2}) ÷ 100 = (?)^{2}{(128 × 10) × 6400

^{1/2}}/100 = ?^{2}(128 × 10 × 80)/100 = ?

^{2}?

^{2 }=128 × 8? = 1024

^{1/2}? = 32.

Hence the correct option is 2.

- Question 32 of 35
##### 32. Question

Quantitative Aptitude**What will come in the place of question mark (?) in the following questions?**39.99 % of (256.039 – 31) × 38.23 = ?

CorrectThe correct answer is

**O****ption 3 i.e. 3420**Application 39.99% of (256.039 – 31) × 38.23 = ? 40% of (256 – 31) × 38 = ?

? = 40% of 225 × 38

? = 90 × 38

? = 3420.

Hence the correct option is 3

IncorrectThe correct answer is

**O****ption 3 i.e. 3420**Application 39.99% of (256.039 – 31) × 38.23 = ? 40% of (256 – 31) × 38 = ?

? = 40% of 225 × 38

? = 90 × 38

? = 3420.

Hence the correct option is 3

UnattemptedThe correct answer is

**O****ption 3 i.e. 3420**Application 39.99% of (256.039 – 31) × 38.23 = ? 40% of (256 – 31) × 38 = ?

? = 40% of 225 × 38

? = 90 × 38

? = 3420.

Hence the correct option is 3

- Question 33 of 35
##### 33. Question

Quantitative Aptitude**What will come in the place of question mark (?) in the following questions?**(623.983 – 140.001)

^{1/2}× (123.945 + 899.923)^{1/2}= ?CorrectThe correct answer is

**Option 1 i.e. 704.**Application (623.983 – 140.001) ^{1/2}× (123.945 + 899.923)^{1/2}= ?? = (624 – 140)

^{1/2}× (124 + 900)^{1/2}? = 484

^{1/2}× 1024^{1/2}? = 22 × 32

? = 704.

Hence the correct answer is option 1

IncorrectThe correct answer is

**Option 1 i.e. 704.**Application (623.983 – 140.001) ^{1/2}× (123.945 + 899.923)^{1/2}= ?? = (624 – 140)

^{1/2}× (124 + 900)^{1/2}? = 484

^{1/2}× 1024^{1/2}? = 22 × 32

? = 704.

Hence the correct answer is option 1

UnattemptedThe correct answer is

**Option 1 i.e. 704.**Application (623.983 – 140.001) ^{1/2}× (123.945 + 899.923)^{1/2}= ?? = (624 – 140)

^{1/2}× (124 + 900)^{1/2}? = 484

^{1/2}× 1024^{1/2}? = 22 × 32

? = 704.

Hence the correct answer is option 1

- Question 34 of 35
##### 34. Question

Quantitative Aptitude**What will come in the place of question mark (?) in the following questions?**(342.891)

^{1/3}+ (124.789)^{1/3}^{1/3}= ?CorrectThe correct answer is

**Option 2 i.e 67**Application (342.891) ^{1/3}+ (124.789)^{1/3}^{1/3}= ?(343)

^{1/3}+ (125)^{1/3}× (1728)^{1/3}= ?? = 7 + 5 × 12

? = 7 + 60

? = 67

Hence the correct answer is option 2

IncorrectThe correct answer is

**Option 2 i.e 67**Application (342.891) ^{1/3}+ (124.789)^{1/3}^{1/3}= ?(343)

^{1/3}+ (125)^{1/3}× (1728)^{1/3}= ?? = 7 + 5 × 12

? = 7 + 60

? = 67

Hence the correct answer is option 2

UnattemptedThe correct answer is

**Option 2 i.e 67**Application (342.891) ^{1/3}+ (124.789)^{1/3}^{1/3}= ?(343)

^{1/3}+ (125)^{1/3}× (1728)^{1/3}= ?? = 7 + 5 × 12

? = 7 + 60

? = 67

Hence the correct answer is option 2

- Question 35 of 35
##### 35. Question

Quantitative Aptitude**What will come in the place of question mark (?) in the following questions?**59.02 – 345.02 / 22.984 = 11 × ?

CorrectThe correct answer is Option 2 i.e. 4

Application 59.02 – 345.02/22.984 = 11 × ? 59 – (345/23) = 11 × ?

59 – 15 = 11 × ?

44 = 11 × ?

? = 44/11 = 4

? = 4

Hence the correct answer is option 2.

IncorrectThe correct answer is Option 2 i.e. 4

Application 59.02 – 345.02/22.984 = 11 × ? 59 – (345/23) = 11 × ?

59 – 15 = 11 × ?

44 = 11 × ?

? = 44/11 = 4

? = 4

Hence the correct answer is option 2.

UnattemptedThe correct answer is Option 2 i.e. 4

Application 59.02 – 345.02/22.984 = 11 × ? 59 – (345/23) = 11 × ?

59 – 15 = 11 × ?

44 = 11 × ?

? = 44/11 = 4

? = 4

Hence the correct answer is option 2.